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| 1 | |
A difference between calculating the sample mean and the population mean is |
| | A) | Only in the symbols: we use n for the sample mean and N for the population. |
| | B) | We divide the sum of the observations by n – 1 instead of n. |
| | C) | The observations are ranked and select the middle value for the population mean. |
| | D) | The population mean is larger. |
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| 2 | |
Which of the following measures of central tendency is affected most by extreme values? |
| | A) | Median |
| | B) | Mean |
| | C) | Mode |
| | D) | Geometric mean |
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| 3 | |
Which level of measurement is required for the median? |
| | A) | Nominal |
| | B) | Ordinal |
| | C) | Interval |
| | D) | Ratio |
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| 4 | |
Which level of measurement is required for the mode? |
| | A) | Nominal |
| | B) | Ordinal |
| | C) | Interval |
| | D) | Ratio |
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| 5 | |
In a set of observations, which measure of central tendency reports the value that occurs most often? |
| | A) | Mean |
| | B) | Median |
| | C) | Mode |
| | D) | Geometric mean |
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| 6 | |
The weighted mean is a special case of the |
| | A) | Mean. |
| | B) | Median. |
| | C) | Mode. |
| | D) | Geometric mean. |
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| 7 | |
The relationship between the geometric mean and the arithmetic mean is |
| | A) | They will always be the same. |
| | B) | The geometric mean will always be larger. |
| | C) | The geometric mean will be equal to or less than the arithmetic mean. |
| | D) | The arithmetic mean will always be larger than the geometric mean. |
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| 8 | |
In a symmetric distribution |
| | A) | The mean and median are equal. |
| | B) | The mean is the largest measure of location. |
| | C) | The median is the largest measure of location. |
| | D) | The standard deviation is the largest value. |
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| 9 | |
Which of the following statements is true regarding the standard deviation? |
| | A) | It cannot assume a negative value. |
| | B) | If it is zero, then all the data values are the same. |
| | C) | It is in the same units as the mean. |
| | D) | All of the above are all correct. |
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| 10 | |
A disadvantage of the range is |
| | A) | Only two values are used in its calculation. |
| | B) | It is in different units than the mean. |
| | C) | It does not exist for some data sets. |
| | D) | All of above. |
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| 11 | |
The mean deviation is |
| | A) | Based on squared deviations from the mean. |
| | B) | Also called the variance. |
| | C) | Based on absolute values. |
| | D) | Always reported in squared units. |
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| 12 | |
The standard deviation |
| | A) | Is based on squared deviations from the mean. |
| | B) | Is in the same units as the mean. |
| | C) | Uses all the observations in its calculations. |
| | D) | All of the above. |
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| 13 | |
Suppose you compare the mean of raw data and the mean of the same raw data grouped into a frequency distribution. These two means will be |
| | A) | Exactly equal. |
| | B) | The same as the median. |
| | C) | The same as the geometric mean. |
| | D) | Approximately equal. |
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| 14 | |
A sample of five stocks traded on the Nasdaq revealed the following percent changes from yesterday to today.
 <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070951640/354829/ch3image1.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (2.0K)</a>]]>
The mean percent change is |
| | A) | 6.12%. |
| | B) | 7.5%. |
| | C) | 7.48%. |
| | D) | None of the above. |
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| 15 | |
A sample of five stocks traded on the Nasdaq revealed the following percent changes from yesterday to today. <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070951640/354829/ch3image1.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (2.0K)</a>]]> The median percent change is |
| | A) | 6.12%. |
| | B) | 7.5%. |
| | C) | 7.48%. |
| | D) | None of the above. |
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| 16 | |
A sample of five stocks traded on the Nasdaq revealed the following percent changes from yesterday to today. <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070951640/354829/ch3image1.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (2.0K)</a>]]> Determine the range of the values. |
| | A) | 14.1% |
| | B) | 6.12% |
| | C) | 20.9% |
| | D) | None of the above. |
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| 17 | |
A sample of five stocks traded on the Nasdaq revealed the following percent changes from yesterday to today. <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070951640/354829/ch3image1.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (2.0K)</a>]]> Determine the standard deviation. |
| | A) | 7.18% |
| | B) | 64.43% |
| | C) | 8.03% |
| | D) | None of the above. |
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| 18 | |
A sample of five stocks traded on the Nasdaq revealed the following percent changes from yesterday to today. <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070951640/354829/ch3image1.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (2.0K)</a>]]> Find the 63rd percentile. |
| | A) | 7.5% |
| | B) | 8.202% |
| | C) | 3.78% |
| | D) | None of the above. |
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| 19 | |
To find the average percent increase over a period of time, you would use the |
| | A) | Geometric mean |
| | B) | Arithmetic mean |
| | C) | Median |
| | D) | Mode |
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| 20 | |
The standard deviation of a data set with a range greater than zero is computed treating the data as a population. If it is then recalculated treating the data as a sample, the resulting standard deviation will be |
| | A) | higher |
| | B) | lower |
| | C) | The same |
| | D) | Either higher or lower, depending on the data |
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| 21 | |
If the population variance of a set of measurements is 400 square units, the population standard deviation |
| | A) | Is 20 units |
| | B) | Is 200 units |
| | C) | Is 400 units |
| | D) | Cannot be determined |
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| 22 | |
According to Chebyshev’s Theorem, what percent of the observations must be found within two standard deviations of the mean? |
| | A) | 0 |
| | B) | 75 |
| | C) | 89 |
| | D) | 95 |
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| 23 | |
According to the Empirical Rule, if the mean height of basketball players is 184 cm with a standard deviation of 4 cm, what percent of the population would be between 180 and 188 cm in height? |
| | A) | 0 |
| | B) | 68 |
| | C) | 75 |
| | D) | 95 |
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| 24 | |
If the mean of a set of data is 80 and the standard deviation is 4, what is the coefficient of variation? |
| | A) | 2% |
| | B) | 0.5% |
| | C) | 5% |
| | D) | 20% |
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