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| 1 | |
A line has a slope of  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070973199/362684/pom9_ch6_sec5_quiz1_ques1.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (0.0K)</a>]]> and passes through the point (3, –1). Find the equation of the line. |
| | A) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070973199/362684/pom9_ch6_sec5_quiz1_ques1a.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (1.0K)</a>]]> |
| | B) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070973199/362684/pom9_ch6_sec5_quiz1_ques1b.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (1.0K)</a>]]> |
| | C) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070973199/362684/pom9_ch6_sec5_quiz1_ques1c.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (1.0K)</a>]]> |
| | D) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070973199/362684/pom9_ch6_sec5_quiz1_ques1d.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (1.0K)</a>]]> |
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| 2 | |
A line has a slope of –5 and passes through the point (–5, –7). To graph this line, start at the given point. Then, |
| | A) | move right 1 unit and up 5 units. |
| | B) | move right 5 units and up 1 unit. |
| | C) | move right 1 unit and down 5 units. |
| | D) | move right 5 units and down 1 unit. |
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| 3 | |
A line is parallel to the line y = 2x + 3, and passes through the point (1, 1). Find the equation of the line. |
| | A) | y = 2x + 1 |
| | B) | y = 2x – 1 |
| | C) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070973199/362684/pom9_ch6_sec5_quiz1_ques3c.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (1.0K)</a>]]> |
| | D) |  <![CDATA[<a onClick="window.open('/olcweb/cgi/pluginpop.cgi?it=jpg::::/sites/dl/free/0070973199/362684/pom9_ch6_sec5_quiz1_ques3d.jpg','popWin', 'width=NaN,height=NaN,resizable,scrollbars');" href="#"><img valign="absmiddle" height="16" width="16" border="0" src="/olcweb/styles/shared/linkicons/image.gif"> (1.0K)</a>]]> |
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| 4 | |
A line is perpendicular to the line y = –x + 2, and passes through the point (1, 4). Find the equation of the line. |
| | A) | y = –x + 4 |
| | B) | y = –x + 3 |
| | C) | y = x + 4 |
| | D) | y = x + 3 |
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| 5 | |
In the evening, there is a callout charge for any aircraft landing at Wainfleet Airport that wants to purchase fuel. Avgas sells for $1.25/L. Randy bought 100 L of fuel, and paid a total of $135. Write the equation that relates the cost of fuel C to the number of litres purchased n. |
| | A) | C = 1.25n + 10 |
| | B) | C = 1.25n – 10 |
| | C) | C = 10n + 1.25 |
| | D) | C = 10n – 1.25 |
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