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1 | |
If a mated strain grew on plates containing azide, lactose, galactose, and formed T1 plaques, its genotype would be |
| | A) | azides, T1s, lac+, gal+ |
| | B) | azider, T1s, lac+, gal+ |
| | C) | azides, T1s, lac-, gal- |
| | D) | azider, T1r, lac-, gal- |
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2 | |
Based on the gene order described in this experiment, if a mated strain was T1 resistant, it would also be |
| | A) | able to grow on lactose and galactose |
| | B) | able to grow on lactose but unable to grow on galactose |
| | C) | unable to grow on lactose but able to grow on galactose |
| | D) | unable to grow on lactose and galactose |
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3 | |
The purpose of the blender treatment is |
| | A) | To promote the binding between the two strains |
| | B) | To promote the transfer of DNA between the two strains |
| | C) | To separate the mated cells |
| | D) | To promote recombination of the donor DNA into the recipient chromosome |
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4 | |
The reason why it took so long for the gal+ gene to be transferred was because |
| | A) | The gal+ gene was farthest from the origin of transfer. |
| | B) | The gal+ gene is the largest gene. |
| | C) | The gal+ gene does not readily recombine into the recipient chromosome. |
| | D) | The gal+ gene is susceptible to mutation. |
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5 | |
The reason why the researchers did not observe mated cells that were streptomycin sensitive was because |
| | A) | The strs gene in the donor strain was too far from the origin of transfer. |
| | B) | The cells were initially placed on plates with streptomycin, which would kill streptomycin-sensitive cells. |
| | C) | The gene is too large to be transferred. |
| | D) | None of the above. |
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