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Chapter 26: Chemistry in the Environment

Problem of the Week

 
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Teachers Notes:

Problem 1:
3mg O2 x (.001 g /mg) x (1mole O2/32.0 g O2) x 1/1 Liter = 9.38 x 10-5M

Problem 2:
ammonia, NH3, 14.0 g N/ 17.0 g NH3 x 100 = 82.4% N
ammonium biphosphate, (NH4)2PO4, 28.0 g N/131 g (NH4)2PO4 x 100 =21.4 % N
ammonium nitrate, NH4NO3, 28.0 g N/ 80.0 g NH4NO3 x 100 = 35.0% N
ammonium sulfate, (NH4)2SO4, 28.0 g N/ 132 g (NH4)2SO4 x 100 = 21.2% N
urea, N2H4CO, 28.0 g N/ 60.0 g N2H4CO x 100 = 46.7 % N

Problem 3:
1.4 x 109 kilograms of calcium carbonate

a. 1.4 x 109 kg CaCO3 x (1 x 103g/kg) x (1 mol CaCO3/100.1 g CaCO3) = 1.4 x 1010 mol CaCO3
b. 1.4 x 109 kg CaCO3 x (1 x 103g/kg) x ( 1 mol CaCO3 / 100.1 g CaCO3) x (1 mol CO2/ 1 mol CaCO3) x (44.0 g CO2/1 mol CO2) = 6.15 x 1011 g CO2

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